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Question

If $\mathrm{R}$ is the reaction $mg$ weight, $v$ speed of the earth, $r$ radius of the earth, then the centripetal force required is,

$\mathrm{mg}-

Vedclass · Accepted Answer

Increase at the equator

Vedclass · Answer

If $\mathrm{R}$ is the reaction $mg$ weight, $v$ speed of the earth, $r$ radius of the earth, then the centripetal force required is,

$\mathrm{mg}-\mathrm{R}=\frac{\mathrm{mv}^{2}}{\mathrm{r}}$ Or $\mathrm{R}=\mathrm{mg}-\frac{\mathrm{mv}^{2}}{\mathrm{r}}$

When the earth stops rotating, $v=0 .$ Hence, $\mathrm{R}$ increases, thereby increasing the weight at the equator.

Suppose the earth stopped rotating. Then, the weight a body will

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