Angular speed of earth in rad/s , so that bodies on equator may appear weightless is : [Use g = 10,

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7.Gravitation

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The angular speed of earth in $rad/s$, so that bodies on equator may appear weightless is : [Use $g = 10\, m/s^2$ and the radius of earth $= 6.4 \times 10^3\, km$]

A

$1.25 \times {10^{ - 3}}$

B

$1.56 \times {10^{ - 3}}$

C

$1.25 \times {10^{ - 1}}$

D

$1.56$

Solution

$\omega^{\prime}=\sqrt{g / R}=\sqrt{\frac{281}{6.4 \times 10^{6}}}$

$=1.25 \times 10^{-3} \mathrm{\,rad} / \mathrm{s}$

Standard 11

Physics

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