- Home
- Standard 11
- Physics
4-1.Newton's Laws of Motion
hard
The $50\,kg$ homogeneous smooth sphere rests on the $30^{\circ}$ incline $A$ and bears against the smooth vertical wall $B$. Calculate the contact forces at $A$ and $B.$
A
$N _{ A }=\frac{1000}{\sqrt{3}}\,N , \quad N _{ B }=\frac{500}{\sqrt{3}}\,N$
B
$N_B=\frac{1000}{\sqrt{3}}\,N, \quad N_A=\frac{500}{\sqrt{3}}\,N$
C
$N_A=\frac{100}{\sqrt{3}}\,N, \quad N_B=\frac{500}{\sqrt{3}}\,N$
D
$N _{ A }=\frac{1000}{\sqrt{3}}\,N , \quad N _{ B }=\frac{50}{\sqrt{3}}\,N$
Solution
$N_A \sin 60^{\circ}=500$
$N_A=\frac{1000}{\sqrt{3}}$
$N_A \cos 60^{\circ}=N_B \Rightarrow N_B=\frac{500}{\sqrt{3}}$
Standard 11
Physics
Similar Questions
medium
