50, kg homogeneous smooth sphere rests on 30^o incline A and bears against smooth vertical wall B .

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4-1.Newton's Laws of Motion

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The $50\, kg$ homogeneous smooth sphere rests on the $30^o$ incline $A$ and bears against the smooth vertical wall $B$. Calculate the contact force at $A$

A

$\frac{{500}}{{\sqrt 3 }}\,N$

B

$500\,N$

C

$\frac{{1000}}{{\sqrt 3 }}\,N$

D

$1000\,N$

Solution

$N_{A} \cos 30^{\circ}=500 N$

and $N_{A} \sin 30^{\circ}=N_{B}$

On solving these two equations, we get

$N_{A}=\frac{1000}{\sqrt{3}} N$

Standard 11

Physics

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