The molar solubility of $PbI_2$ in $0.2\,M\,\, Pb(NO_3)_2$ solution in terms of solubility product of $PbI_2$ is

The solubility product of $PbI _{2}$ is $8.0 \times 10^{-9} .$ The solubility of lead iodide in $0.1$ molar solution of lead nitrate is $x \times 10^{-6} \,mol / L$. The value of $x$ is ……. .(Rounded off to the nearest integer)

$[$ Given $: \sqrt{2}=1.41]$

Predict whether a precipitate of $(PbI_{2})$ will be formed or not on mixing $20$ $mL$ of $3 \times {10^{ – 3}}$ $M$ $Pb{\left( {N{O_3}} \right)_2}$ solution with $80$ $mL$ of $2 \times {10^{ – 3}}$ $M$ $NaI$ solution. $K_{sp}$ for lead iodide ( $PbI_{2}$ ) is $6.0 \times {10^{ – 9}}$

The solubility product by Lead sulphate, $PbS{O_4}$ is $1.3 \times {10^{ – 8}}$ calculate its solubility in pure water. The molecular mass of $PbS{O_4}$ $= 303$ $g$ $mol^{-1}$.

The solubility product of $AB_2$ is $8\times 10^{-5}\,M^3$ . If the salt is $80\,\%$ dissociated in saturated solution, find the solubility of the salt.

Given [Molar mass $(AB_2) = 360$ ]