Solubility product by Lead sulphate, PbS{O₄} is 1.3 × {10^{ - 8}} calculate its solubility

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6-2.Equilibrium-II (Ionic Equilibrium)

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The solubility product by Lead sulphate, $PbS{O_4}$ is $1.3 \times {10^{ - 8}}$ calculate its solubility in pure water. The molecular mass of $PbS{O_4}$ $= 303$ $g$ $mol^{-1}$.

Option A

Option B

Option C

Option D

Solution

$3.45 \times 10^{-2} \mathrm{~g} \mathrm{~L}^{-1}$

Standard 11

Chemistry

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