{K_{sp}} of BaS{O₄} is 1.1 × {10^{ - 10}} . Will a precipitate form when equal volume of 2 × {10

English

Gujarati

Hindi

6-2.Equilibrium-II (Ionic Equilibrium)

medium

The ${K_{sp}}$ of $BaS{O_4}$ is $1.1 \times {10^{ - 10}}$. Will a precipitate form when equal volume of $2 \times {10^{ - 4}}$ $BaC{l_2}$ and $5.0 \times {10^{ - 3}}$ $M$ ${H_2}S{O_4}$ solution are mixed ? Explain by calculation.

Option A

Option B

Option C

Option D

Solution

$\mathrm{Q}_{s p}$ of $\mathrm{BaSO}_{4}=2.5 \times 10^{-7}$, So no PPt. will be formed

Standard 11

Chemistry

Share

Similar Questions

The solubility of salt of weak acid $MX$ (e.g. phosphoric) is increase at tower $pH$ explain with equation.

hard

The saturated solution of $A{g_2}S{O_4}$ is $2.5 \times {10^{ – 2}}\,M.$ Its solubility product $({K_{sp}})$ is

medium

What is the $pH$ of a saturated solution of $Cu(OH)_2$ ? $(K_{sp} = 4.0 \times 10^{-6}$ )

medium

What is the molar solubility of $Ag_2CO_3\, (K_{sp} = 4 \times 10^{-13})$ in $0.1\, M\, Na_2CO_3$ solution ?

medium

The solubility product of a sparingly soluble salt $A _{2} X _{3}$ is $1.1 \times 10^{-23}$. If specific conductance of the solution is $3 \times 10^{-5} \,S\, m ^{-1}$, the limiting molar conductivity of the solution is $x \times 10^{-3} \,S\, m ^{2}\, mol ^{-1}$. The value of $x$ is …

hard

(JEE MAIN-2022)