- Home
- Standard 11
- Physics
1.Units, Dimensions and Measurement
easy
The acceleration due to gravity is measured on the surface of earth by using a simple pendulum. If $\alpha$ and $\beta$ are relative errors in the measurement of length and time period respectively, then percentage error in the measurement of acceleration due to gravity is
A
$\left(\alpha+\frac{1}{2} \beta\right) \times 100$
B
$(\alpha-2 \beta)$
C
$(2 \alpha+\beta) \times 100$
D
$(\alpha+2 \beta) \times 100$
Solution
(d)
$T=2 \pi \sqrt{\frac{L}{g}}$
$\Rightarrow T^2=4 \pi^2 \frac{L}{g}$
$\frac{\Delta g}{g} \times 100 \%=\frac{\Delta L}{L} \times 100 \%+\frac{2 \Delta T}{T} \times 100 \%$
$\frac{\Delta g}{g} \times 100 \%=(\alpha+2 \beta) \times 100$
Standard 11
Physics
Similar Questions
easy