The acceleration of a moving body can be found from

Two trains travelling on the same track are approaching each other with equal speeds of $40\ m/s$ . The drivers of the trains begin to decelerate simultaneously when they are just $2.0\ km$ apart. Assuming the decelerations to be uniform and equal, the value of the deceleration to barely avoid collision should be..........$m/s^2$

If the velocity of a particle is $(10 + 2t^2) m/s$, then the average acceleration of the particle between $2s$ and $5s$ is..........$m/s^2$

Your friend driving his car overtakes your car on the highway. Which of the following statement must be true at the instant he is passing you? Assume the cars as point particles.

The velocity $v$ of a body moving along a straight line varies with time $t$ as $v=2 t^2 e^{-t}$, where $v$ is in $m / s$ and $t$ is in second. The acceleration of body is zero at $t=$

The velocity $(v)$-time $(t)$ graph for a particle moving along $x$-axis is shown in the figure. The corresponding position $(x)$ - time $(t)$ is best represented by