Gujarati
Hindi
10-1.Circle and System of Circles
normal

The angle at which the circles $(x - 1)^2 + y^2 = 10$ and $x^2 + (y - 2)^2 = 5$ intersect is

A

$\frac{\pi }{6}$

B

$\frac{\pi }{4}$

C

$\frac{\pi }{3}$

D

$\frac{\pi }{2}$

Solution

$cos\theta=\frac{{10 + 5 – 5}}{{2\,\cdot\,\sqrt {10} \,\cdot\,\sqrt 5 }}$   $ = \frac{1}{{\sqrt 2 }}$

$\Rightarrow\theta =$$\frac{\pi }{4}$

Standard 11
Mathematics

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