The angle between vector $\vec{Q}$ and the resultant of $(2 \overrightarrow{\mathrm{Q}}+2 \overrightarrow{\mathrm{P}})$ and $(2 \overrightarrow{\mathrm{Q}}-2 \overrightarrow{\mathrm{P}})$ is:

  • [JEE MAIN 2024]
  • A

    $0^{\circ}$

  • B

    $\tan ^{-1} \frac{(2 \overrightarrow{\mathrm{Q}}-2 \overrightarrow{\mathrm{P}})}{2 \overrightarrow{\mathrm{Q}}+2 \overrightarrow{\mathrm{P}}}$

  • C

    $\tan ^{-1}\left(\frac{P}{Q}\right)$

  • D

    $\tan ^{-1}\left(\frac{2 Q}{P}\right)$

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