Gujarati
3-2.Motion in Plane
easy

The angular speed of seconds needle in a mechanical watch is

A$\frac{\pi }{{30}}\,rad/s$
B$2\pi \,rad/s$
C$\pi \,rad/s$
D$\frac{{60}}{\pi }\,rad/s$

Solution

(a)$\omega = \frac{{2\pi }}{T} = \frac{{2\pi }}{{60}} = \frac{\pi }{{30}}\,rad/s$
Standard 11
Physics

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