Area of cross section of wides tube shown in figure is 800,cm^2 . If a mass of 12,kg is placed on ma

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9-1.Fluid Mechanics

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The area of cross section of the wides tube shown in the figure is $800\,cm^2$. If a mass of $12\,kg$ is placed on the massless piston, the difference in the heights $h$ in the level of water in two tubes ........ $m$

A

$10$

B

$6$

C

$15$

D

$2$

Solution

$\mathrm{P}_{\text {excess }}=\rho \mathrm{gh}$

$\frac{\mathrm{mg}}{\mathrm{A}}=\rho \mathrm{gh} \Rightarrow \mathrm{h}=\frac{\mathrm{m}}{\rho \mathrm{A}}=15 \mathrm{cm}$

Standard 11

Physics

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