Gujarati
Hindi
4.Average
medium

The arithmetie mean of the scores of a group of students in a test was $52 .$ The brightest $20 \%$ of them secured a mean score of $80$ and the dullest $25 \%$ a mean score of $31.$ The mean score of remaining $55 \%$ is

A

$45$

B

$50$

C

$51.4$ approx

D

$54.6$ approx

Solution

Let the number of students be $100.$

Then total score $=52 \times 100=5200$

first $20 \%$ scored $=20 \times 80=1600$

last $25 \%$ scored $=25 \times 31=775$

$\therefore$ Remaining $55 \%$ student's score $=5200-1600-775=2825$

$\therefore$ Average score among $55 \%=\frac{2825}{55}=51.4$ approx

Standard 13
Quantitative Aptitude

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