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- Quantitative Aptitude
4.Average
medium
The average daily wages of $A, B$ and $C$ is $Rs.\, 120 .$ If $B$ earns $Rs.\,40$ more than $C$ per $day$ and $A$ earns double of what $C$ earns per $day,$ the wages of $A$ per $day$ is (in $Rs.$)
A
$80$
B
$120$
C
$160$
D
$100$
Solution
Let, daily wages of $C=x$
Then, daily wages of $A=2 x$
and, daily wages of $B =x+40$
Hence, average daily wages of $A, B$ and $C$
$=\frac{x+2 x+x+40}{3}=\frac{4 x+40}{3}$
$\therefore \quad \frac{4 x+40}{3}=120$ or, $4 x+40=360$
$\Rightarrow \quad 4 x=320$ or, $x=80$
$\therefore$ Daily wages of $A=2 \times 80=Rs. 160$
Standard 13
Quantitative Aptitude