Average daily wages of A, B and C is Rs., 120 . If B earns Rs.,40 more than C per day and A earns do

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The average daily wages of $A, B$ and $C$ is $Rs.\, 120 .$ If $B$ earns $Rs.\,40$ more than $C$ per $day$ and $A$ earns double of what $C$ earns per $day,$ the wages of $A$ per $day$ is (in $Rs.$)

A

$80$

B

$120$

C

$160$

D

$100$

Solution

Let, daily wages of $C=x$

Then, daily wages of $A=2 x$

and, daily wages of $B =x+40$

Hence, average daily wages of $A, B$ and $C$

$=\frac{x+2 x+x+40}{3}=\frac{4 x+40}{3}$

$\therefore \quad \frac{4 x+40}{3}=120$ or, $4 x+40=360$

$\Rightarrow \quad 4 x=320$ or, $x=80$

$\therefore$ Daily wages of $A=2 \times 80=Rs. 160$

Standard 13

Quantitative Aptitude

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