Average degree of freedom per molecule of a gas is 6 . gas performs 25 J work, while expanding

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12.Kinetic Theory of Gases

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The average degree of freedom per molecule of a gas is $6$. The gas performs $25\ J$ work, while expanding at constant pressure. The heat absorbed by the gas is .... $J$

A

$75$

B

$100$

C

$150$

D

$125$

Solution

For constant pressure process.

Work done $(\mathrm{W})=\mathrm{nR} \Delta \mathrm{T}$

$\therefore \Delta \mathrm{T}=\left(\frac{25}{\mathrm{nR}}\right)$

Now, for above process $f=6$

So $C_{p}\left(1+\frac{f}{2}\right) R=4 R$

Heat absorbed $=\mathrm{nC}_{\mathrm{p}} \Delta \mathrm{T}$

$=n \times 4 R \times \frac{25}{n R}=100 \mathrm{J}$

Standard 11

Physics

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