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4.Average
hard
The average marks obtained by $40$ students of a class is $86 .$ If the $5$ highest marks are removed, the average reduces by one mark. The average marks of the top $5$ students is
A
$92$
B
$96$
C
$93$
D
$97$
Solution
Average $_{40}=86$
$Sum _{40}=40 \times 86=3440$
When top $5$ marks are removed, the average reduced by $1$ Now average $=86-1=85$
Number of students now becomes $=40-5=35$
So total of remaining students $=35 \times 85=2975$
So total marks of top $5$ students $=3440-2975=465$
$\text { Average }_{5}=\frac{465}{5}=93$
Standard 13
Quantitative Aptitude
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