Gujarati
Hindi
4.Average
hard

The average marks obtained by $40$ students of a class is $86 .$ If the $5$ highest marks are removed, the average reduces by one mark. The average marks of the top $5$ students is

A

$92$

B

$96$

C

$93$

D

$97$

Solution

Average $_{40}=86$

$Sum _{40}=40 \times 86=3440$

When top $5$ marks are removed, the average reduced by $1$ Now average $=86-1=85$

Number of students now becomes $=40-5=35$

So total of remaining students $=35 \times 85=2975$

So total marks of top $5$ students $=3440-2975=465$

$\text { Average }_{5}=\frac{465}{5}=93$

Standard 13
Quantitative Aptitude

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