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4.Average
medium
The average of $50$ numbers is $30.$ If two numbers, $35$ and $40$ are discarded, then the average of the remaining numbers is nearly.
A
$28.32$
B
$28.78$
C
$29.27$
D
$29.68$
Solution
The sum of $50$ numbers $=50 \times 30=1500$
Discarding $35$ and $40,$ we get
Average of remaining $48$ numbers $=\frac{1500-35-40}{48}$
$=\frac{1500-75}{48}=\frac{1425}{48}=29.68$
Standard 13
Quantitative Aptitude