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4.Average
medium
The average of $50$ numbers is $38 .$ If two numbers, namely, $45$ and $55$ are discarded, what is the average of the remaining numbers ?
A
$37.5$
B
$38.5$
C
$39.5$
D
$36.5$
Solution
Sum total of $50$ numbers $=50 \times 38=1900$
Sum total of the remaining $48$ numbers
$=1900-(45+55)=1800$
$\therefore$ Average $=\frac{1800}{48}=37.5$
Standard 13
Quantitative Aptitude