Average resisting force that must act on a 5 ,kg mass to reduce its speed from 65 ,cm/s to 15 ,cm/s

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4-1.Newton's Laws of Motion

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The average resisting force that must act on a $5 \,kg$ mass to reduce its speed from $65 \,cm/s$ to $15 \,cm/s$ in $0.2\,s$ is .......... $N$

A

$12.5$

B

$25$

C

$50$

D

$100$

Solution

(a)$F = m\,\left( {\frac{{v – u}}{t}} \right) = \frac{{5(65 – 15) \times {{10}^{ – 2}}}}{{0.2}} = 12.5\,N$

Standard 11

Physics

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