The bond length the species ${O_2},O_2^ + $ and $O_2^ - $ are in the order of
$O_2^ - > {O_2} > O_2^ + $
$O_2^ + > O_2^ - > {O_2}$
${O_2} > O_2^ + > O_2^ - $
$O_2^ + > {O_2} > O_2^ - $
Give answer of following questions.
$(i)$ Give molecular orbitals and type form by $\mathrm{LCAO}$ from $2{\rm{s}},2{{\rm{p}}_{\rm{x}}},2{{\rm{p}}_{\rm{y}}}$ and $2{{\rm{p}}_{\rm{z}}}$
$(ii)$ ${\rm{L}}{{\rm{i}}_2},{\rm{B}}{{\rm{e}}_2},{{\rm{C}}_2},{{\rm{N}}_2},{{\rm{O}}_2}{\rm{,}}{{\rm{F}}_2}$ for these molecule give energy other.
Match List $I$ with List $II$ :
List $I$ (Molecule Species) |
List $I$ ( Property Shape ) |
$A$ $\mathrm{SO}_2 \mathrm{Cl}_2$ | $I$ Paramagnetic |
$B$ $NO$ | $II$ Diamagnetic |
$C$ $\mathrm{NO}_2^{-}$ | $III$ Tetrahedral |
$D$ $\mathrm{I}_3^{-}$ | $IV$ Linear |
Choose the correct answer from the options given below :
The bond order of a molecule is given by
The species having no $P\pi - P\pi $ bond but has bond order equal to $O_2$
Which of the following statement is correct for peroxide ion
$A.$ has completely filled antibonding molecular orbitals
$B.$ is diamagnetic
$C.$ has bond order one
$D.$ is isoelectronic with Neon