The bond length the species {O_2},O_2^ + and | vedclass

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Question

(a) As bond order increase bond length decrease the bond order of species are

$ = \frac{{{\rm{number \,of\, bonding \,electron - Number \,of \,}}a{

Vedclass · Accepted Answer

$O_2^ - > {O_2} > O_2^ + $

Vedclass · Answer

(a) As bond order increase bond length decrease the bond order of species are

$ = \frac{{{\rm{number \,of\, bonding \,electron - Number \,of \,}}a{\rm{.}}b{\rm{. electron}}}}{2}$

For ${O_2} = \frac{{10 - 6}}{2} = 2$ ;

$O_2^ + = \frac{{10 - 5}}{2} = 2.5$

$O_2^ - = \frac{{10 - 7}}{2} = 1.5$

So, bond order $O_2^ + > {O_2} > O_2^ - $

The bond length the species ${O_2},O_2^ + $ and $O_2^ - $ are in the order of

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