The bond length the species ${O_2},O_2^ + $ and $O_2^ - $ are in the order of

  • A

    $O_2^ - > {O_2} > O_2^ + $

  • B

    $O_2^ + > O_2^ - > {O_2}$

  • C

    ${O_2} > O_2^ + > O_2^ - $

  • D

     $O_2^ + > {O_2} > O_2^ - $

Similar Questions

Give answer of following questions.

$(i)$ Give molecular orbitals and type form by $\mathrm{LCAO}$ from $2{\rm{s}},2{{\rm{p}}_{\rm{x}}},2{{\rm{p}}_{\rm{y}}}$ and $2{{\rm{p}}_{\rm{z}}}$ 

$(ii)$ ${\rm{L}}{{\rm{i}}_2},{\rm{B}}{{\rm{e}}_2},{{\rm{C}}_2},{{\rm{N}}_2},{{\rm{O}}_2}{\rm{,}}{{\rm{F}}_2}$ for these molecule give energy other.

Match List $I$ with List $II$ :

List $I$ (Molecule  Species)

List $I$ ( Property  Shape )

$A$ $\mathrm{SO}_2 \mathrm{Cl}_2$ $I$ Paramagnetic
$B$ $NO$ $II$ Diamagnetic
$C$ $\mathrm{NO}_2^{-}$ $III$ Tetrahedral
$D$  $\mathrm{I}_3^{-}$ $IV$ Linear

Choose the correct answer from the options given below :

  • [JEE MAIN 2024]

The bond order of a molecule is given by

The species having no $P\pi  - P\pi $ bond but has bond order equal to $O_2$

Which of the following statement is correct for peroxide ion

$A.$  has completely filled antibonding molecular orbitals
$B.$  is diamagnetic
$C.$   has bond order one
$D.$  is isoelectronic with Neon