Bond order in {N₂} molecule is

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4.Chemical Bonding and Molecular Structure

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The bond order in ${N_2}$ molecule is

A

$1$

B

$2$

C

$3$

D

$4$

Solution

(c)The Bond order in ${N_2}$ molecule is 3, $N \equiv N$ Here, ${N_b} = 2 + 4 + 2 = 8$ and ${N_a} = 2$

${\rm{B}}{\rm{.O}}. = (\,8 – 2)/2 = 3.$

Standard 11

Chemistry

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