- Home
- Standard 11
- Chemistry
4.Chemical Bonding and Molecular Structure
medium
$O_2^ + $ का बन्ध क्रम समान है
A
$N_2^ + $
B
$C{N^ - }$
C
$CO$
D
$N{O^ + }$
Solution
$O_2^ + (15{e^ – }) = K{K^*}{(\sigma 2s)^2}{({\sigma ^*}2s)^2}{(\sigma 2{p_x})^2}$
${(\pi 2{p_y})^2}{(\pi 2{p_z})^2}{({\pi ^*}2{p_y})^1}{({\pi ^*}2{p_z})^0}$
इसलिये, बन्धक्रम $ = \frac{1}{2}(10 – 5) = 2.5$
$N_2^ + (13{e^ – }) = K{K^*}{(\sigma 2s)^2}{({\sigma ^*}2s)^2}{(\sigma 2{p_x})^2}$
${(\pi \,2{p_y})^2}{(\pi \,2{p_z})^1}$
इसलिये बन्धक्रम $ = \frac{1}{2}(9 – 4) = 2.5$
Standard 11
Chemistry
