The brakes applied to a car produce an acceleration of $6\, m s ^{-2}$ in the opposite direction of motion. If the car takes $2\, s$ to stop after the application of the brakes, calculate the distance it travels during this time.

Vedclass pdf generator app on play store
Vedclass iOS app on app store

Given $a=-6 m s ^{-2}, t=2 s , v=0 m s ^{-1}$

$(i)$ Using the equation $v=u+a t,$ we have

$u=v-a t=0-(-6) \times 2$

$=12 m s ^{-1}$

$(ii)$ Now, using the expression $S=u t+1 / 2 a t^{2}$

we have $S=12 \times 2+\frac{1}{2} \times-6 \times(2)^{2}=12 m$

Similar Questions

What is the slope of the displacement $-$ time graph when the body has uniform motion ?

An athlete completes one round of a circular track of diameter $49 \,m$ in $20 \,s$. Calculate the distance covered and displacement at the end of $30 \,s$.

Give one similarity and one dissimilarity between the two graphs

State the type of motion represented by the given graph.

What is meant by uniform motion ? Can you think of an example of a body in uniforim motion ?