The capacitance of a parallel plate capacitor is $C$ when the region between the plate has air. This region is now filled with a dielectric slab of dielectric constant $k$. The capacitor is connected to a cell of $emf$ $E$, and the slab is taken out
The capacitance of a parallel plate capacitor is $C$ when the region between the plate has air. This region is now filled with a dielectric slab of dielectric constant $k$. The capacitor is connected to a cell of $emf$ $E$, and the slab is taken out
- A
charge $CE(k - 1)$ flows through the cell
- B
energy $E^2C(k - 1)$ is absorbed by the cell.
- C
the external agent has to do $\frac{1}{2}E^2 C(k - 1)$ amount of work to take the slab out.
- D
all of the above
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