The chance of getting a doublet with $2$ dice is
$\frac{2}{3}$
$\frac{1}{6}$
$\frac{5}{6}$
$\frac{5}{{36}}$
Consider the experiment of rolling a die. Let $A$ be the event 'getting a prime number ', $B$ be the event 'getting an odd number '. Write the sets representing the events $^{\prime}$ not $A\,^{\prime}$.
Out of $60 \%$ female and $40 \%$ male candidates appearing in an exam, $60\%$ candidates qualify it. The number of females qualifying the exam is twice the number of males qualifying it. A candidate is randomly chosen from the qualified candidates. The probability, that the chosen candidate is a female, is.
Let $\Omega$ be the sample space and $A \subseteq \Omega$ be an event. Given below are two statements :
$(S1)$ : If $P ( A )=0$, then $A =\phi$
$( S 2)$ : If $P ( A )=$, then $A =\Omega$
Then
From the word `$POSSESSIVE$', a letter is chosen at random. The probability of it to be $S$ is
Three coins are tossed once. Let $A$ denote the event ' three heads show ', $B$ denote the event ' two heads and one tail show ' , $C$ denote the event ' three tails show and $D$ denote the event 'a head shows on the first coin '. Which events are Compound ?