Gujarati
14.Probability
easy

The chance of getting a doublet with $2$ dice is

A

$\frac{2}{3}$

B

$\frac{1}{6}$

C

$\frac{5}{6}$

D

$\frac{5}{{36}}$

Solution

(b) Total number of outcomes $ = 36$

Favourable number of outcomes $= 6$

$i.e.$, $(1, 1), (2, 2), (3, 3), (4, 4), (5, 5), (6, 6),$

$\therefore$ Required probability $ = \frac{6}{{36}} = \frac{1}{6}.$

Standard 11
Mathematics

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