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14.Probability
easy
The two events $A$ and $B$ have probabilities $0.25$ and $0.50$ respectively. The probability that both $A$ and $B$ occur simultaneously is $0.14$. Then the probability that neither $A$ nor $B$ occurs is
A
$0.39$
B
$0.25$
C
$0.904$
D
None of these
(IIT-1980)
Solution
(a) $P({A^c} \cap {B^c}) = 1 – P(A \cup B)$
$ = 1 – [0.25 + 0.5 – 0.14] = 0.39.$
Standard 11
Mathematics
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