Chance of throwing at least 9 in a single throw with two dice, is

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14.Probability

easy

The chance of throwing at least $9$ in a single throw with two dice, is

A

$\frac{1}{{18}}$

B

$\frac{5}{{18}}$

C

$\frac{7}{{18}}$

D

$\frac{{11}}{{18}}$

Solution

(b) Ways $\begin{array}{*{20}{c}}9&{10}&{11}&{12}\\ \downarrow & \downarrow & \downarrow & \downarrow \\4&3&2&1\end{array}$

Hence the required probability $ = \frac{{10}}{{36}} = \frac{5}{{18}}.$

Standard 11

Mathematics

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