Circuit shown below is working as a 8 mathrm{V}dc regulated voltage source. When 12 mathrm{V} is use

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14.Semiconductor Electronics

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The circuit shown below is working as a $8\; \mathrm{V}\;dc$ regulated voltage source. When $12 \;\mathrm{V}$ is used as input, the power dissipated (in $\mathrm{mW}$ ) in each diode is

(considering both zener diodes are identical)

A

$20$

B

$8$

C

$24$

D

$40$

(JEE MAIN-2020)

Solution

Current in circuit $=\frac{4}{400}=\frac{1}{100} \mathrm{A}$

So power dissipited in each diode $=$ $\mathrm{VI}$

$=4 \times \frac{1}{100} \;\mathrm{W}$

$=40 \times 10^{-3}\; \mathrm{mW}$

Standard 12

Physics

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