Two Zener diodes ( A and B ) having breakdown voltages of 6, V and 4, V respectively, are connected

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14.Semiconductor Electronics

hard

Two Zener diodes ($A$ and $B$) having breakdown voltages of $6\, V$ and $4\, V$ respectively, are connected as shown in athe circuit below. The output voltage $V _{0}$ variation with input voltage linearly increasing with time, is given by : $\left( V _{\text {input }}= OV \right.$ at $\left. t =0\right)$ (figures are qualitative)

(JEE MAIN-2020)

Solution

Till input voltage Reaches $4V$ No zener is in Breakdown Region So $V _{0}= V _{ i }$ Then Now when $V _{ i }$ changes between $4 V$ to $6 V$ One Zener with $4 V$ will Breakdown are $P.D$. across This zener will become constant and Remaining Potential will drop. acro

Resistance in series with $4 V$ Zener.

Now current in circuit increases Abruptly and source must have an internal resistance due to which. Some potential will get drop across the source also so correct graph between $V _{0}$ and $t.$ will be

We have to Assume some resistance in series with source.

Standard 12

Physics