The compound interest (In ₹) on ₹ 10000 at 20 | vedclass

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Question

(b) Here, $P=10000, R=20$ and $t=\frac{3}{2}$

$\begin{aligned} 	herefore \quad CI &=P\left[\left(1+\frac{R}{100 	imes 2}ight)^{2 t}-1ight

Vedclass · Accepted Answer

$3310$

Vedclass · Answer

(b) Here, $P=10000, R=20$ and $t=\frac{3}{2}$

$\begin{aligned} 	herefore \quad CI &=P\left[\left(1+\frac{R}{100 	imes 2}ight)^{2 t}-1ight] \ &=10000\left[\left(1+\frac{20}{100 	imes 2}ight)^{2 	imes \frac{3}{2}}-1ight] \end{aligned}$

$=10000\left[\left(\frac{11}{10}ight)^{3}-1ight]$

$=10000\left(\frac{11 	imes 11 	imes 11}{10 	imes 10 	imes 10}-1ight)$

$=\frac{10000 	imes 331}{1000}=₹ 3310$

The compound interest (In ₹) on ₹ $10000$ at $20 \%$ per annum at the end of $1$ year $6$ months if the interest is calculated half-yearly will be

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