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6.Interest
easy
The compound interest on a certain sum for $2$ years at $10 \%$ per annum is ₹ $525 .$ The simple interest (In ₹) on the same sum for double the time at half the rate per cent per annum is
A
$400$
B
$500$
C
$600$
D
$800$
Solution
C.I. $=P\left[\left(1+\frac{10}{100}\right)^{2}-1\right]=525$
S.I. $=\frac{P \times 4 \times 5}{100}=\frac{P}{5}$
Substituting from (1), we get
$\begin{aligned} \text { S.I. }=\frac{P}{5} &=\frac{525}{\left[\left(\frac{11}{10}\right)^{2}-1\right] \times 5} \\ &=\frac{105 \times 10^{2}}{\left(11^{2}-10^{2}\right)}=\frac{10500}{21 \times 1}=₹ 500 \end{aligned}$
Standard 13
Quantitative Aptitude
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