The compound interest on a certain sum for 2 | vedclass

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Question

C.I. $=P\left[\left(1+\frac{10}{100}ight)^{2}-1ight]=525$

S.I. $=\frac{P 	imes 4 	imes 5}{100}=\frac{P}{5}$

Substituting from (1), we get

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$500$

Vedclass · Answer

C.I. $=P\left[\left(1+\frac{10}{100}ight)^{2}-1ight]=525$

S.I. $=\frac{P 	imes 4 	imes 5}{100}=\frac{P}{5}$

Substituting from (1), we get

$\begin{aligned} 	ext { S.I. }=\frac{P}{5} &=\frac{525}{\left[\left(\frac{11}{10}ight)^{2}-1ight] 	imes 5} \ &=\frac{105 	imes 10^{2}}{\left(11^{2}-10^{2}ight)}=\frac{10500}{21 	imes 1}=₹ 500 \end{aligned}$

The compound interest on a certain sum for $2$ years at $10 \%$ per annum is ₹ $525 .$ The simple interest (In ₹) on the same sum for double the time at half the rate per cent per annum is

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