Condition ( a · b )^2=a^2 b^2 is satisfied when

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3-1.Vectors

easy

The condition $( a \cdot b )^2=a^2 b^2$ is satisfied when

A$a$ is parallel to $b$

B$a \neq b$

C$a \cdot b =1$

D$a \perp b$

Solution

(a)
$( a \cdot b )^2=a^2 b^2 \cos ^2 \theta=a^2 b^2$
$\therefore \quad \theta=0^{\circ}$

Standard 11

Physics

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