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The conducting spherical shells shown in the figure are connected by a conductor. The capacitance of the system is

$4\pi {\varepsilon _0}\,\frac{{ab}}{{b - a}}$
$4\pi {\varepsilon _0}\,a$
$4\pi {\varepsilon _0}\,b$
$4\pi {\varepsilon _0}\,\frac{{{a^2}}}{{b - a}}$
Solution
Hence, the capacitance of the system is the capacitance due to outer sphere of radius $\mathrm{b}.$
$\therefore \quad \mathrm{C}=4 \pi \varepsilon_{0} \mathrm{b}$
Similar Questions
In steady state heat conduction, the equations that determine the heat current $j ( r )$ [heat flowing per unit time per unit area] and temperature $T( r )$ in space are exactly the same as those governing the electric field $E ( r )$ and electrostatic potential $V( r )$ with the equivalence given in the table below.
Heat flow | Electrostatics |
$T( r )$ | $V( r )$ |
$j ( r )$ | $E ( r )$ |
We exploit this equivalence to predict the rate $Q$ of total heat flowing by conduction from the surfaces of spheres of varying radii, all maintained at the same temperature. If $\dot{Q} \propto R^{n}$, where $R$ is the radius, then the value of $n$ is