The correct molecular orbital diagram for $\mathrm{F}_2$ molecule in the ground state is
Match each of the diatomic molecules in Column $I$ with its property / properties in Column $II$.
Column $I$ | Column $II$ |
$(A)$ $\mathrm{B}_2$ | $(p)$ Paramagnetic |
$(B)$ $\mathrm{N}_2$ | $(q)$ Undergoes oxidation |
$(C)$ $\mathrm{O}_2^{-}$ | $(r)$ Undergoes reduction |
$(D)$ $\mathrm{O}_2$ | $(s)$ Bond order $\geq 2$ |
$(t)$ Mixing of ' $\mathrm{s}$ ' and ' $\mathrm{p}$ ' orbitals |
In which of the following processes, the bond order increases and paramagnetic character changes to diamagnetic one?
Which of the following is paramagnetic ?
Use the molecular orbital energy level diagram to show that $\mathrm{N}_{2}$ would be expected to have a triple bond, $\mathrm{F}_{2}$ a single bond and $\mathrm{Ne}_{2}$ no bond.
$AX$ is a covalent diatomic molecule where $A$ and $X$ are second row elements of periodic table. Based on Molecular orbital theory, the bond order of $AX$ is $2.5$. The total number of electrons in $AX$ is ........... (Round off to the Nearest Integer).