Cost price of 12 tables is equal to selling price of 16 tables. loss percent is

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7.Profit and Loss

medium

The cost price of $12$ tables is equal to the selling price of $16$ tables. The loss percent is

A

$15$

B

$20$

C

$25$

D

$30$

Solution

$CP$ of $12$ tables $=S P$ of $16$ tables

$\frac{C P \text { of } 1 \text { table }}{\text { SP of } 1 \text { table }}=\frac{16}{12}=\frac{4}{3}$

$\%$ Loss $=\frac{4-3}{4} \times 100=25 \%$

Standard 13

Quantitative Aptitude

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