9-1.Fluid Mechanics
medium

The density of ice is $0.9 \,g / cm ^3$. What percentage by volume of the block of ice floats outside the water is ..........$\%$

A

$10$

B

$45$

C

$75$

D

$90$

Solution

The forces acting on the ice must balance each other.

Hence buoyant force acting upwards = Weight of the ice

$\Longrightarrow V_{i m m} \rho g=V d g$

$\Longrightarrow \frac{V_{i m m}}{V}=\frac{d}{\rho}=0.9$

Hence, fraction of ice outside water $=1-0.9=0.1$

$=0.1\times 100\%=10\%$

Standard 11
Physics

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