Your friend driving his car overtakes your car on the highway. Which of the following statement must be true at the instant he is passing you? Assume the cars as point particles.
Your friend driving his car overtakes your car on the highway. Which of the following statement must be true at the instant he is passing you? Assume the cars as point particles.
- A
Your speed and his speed are the same.
- B
Your acceleration and his acceleration are the same
- C
Your position on the highway is the same as his position on the highway
- D
He also observes that you overtake his car.
Similar Questions
Two trains travelling on the same track are approaching each other with equal speeds of $40\ m/s$ . The drivers of the trains begin to decelerate simultaneously when they are just $2.0\ km$ apart. Assuming the decelerations to be uniform and equal, the value of the deceleration to barely avoid collision should be..........$m/s^2$
Two trains travelling on the same track are approaching each other with equal speeds of $40\ m/s$ . The drivers of the trains begin to decelerate simultaneously when they are just $2.0\ km$ apart. Assuming the decelerations to be uniform and equal, the value of the deceleration to barely avoid collision should be..........$m/s^2$
A particle is projected with velocity $v_{0}$ along $x-$ axis. A damping force is acting on the particle which is proportional to the square of the distance from the origin i.e., $ma =-\alpha x ^{2}.$ The distance at which the particle stops:
A particle is projected with velocity $v_{0}$ along $x-$ axis. A damping force is acting on the particle which is proportional to the square of the distance from the origin i.e., $ma =-\alpha x ^{2}.$ The distance at which the particle stops:
- [JEE MAIN 2021]
On what factors, does the stopping distance depend ?
On what factors, does the stopping distance depend ?
Equation of motion of a body is $\frac{d v}{d t}=-4 v+8$, where $v$ is the velocity in $m / s$ and $t$ is the time in second. Initial velocity of the particle was zero. Then,
Equation of motion of a body is $\frac{d v}{d t}=-4 v+8$, where $v$ is the velocity in $m / s$ and $t$ is the time in second. Initial velocity of the particle was zero. Then,
A particle of unit mass undergoes one dimensional motion such that its velocity varies according to $ v(x)= \beta {x^{ - 2n}}$, where $\beta$ and $n$ are constants and $x$ is the position of the particle. The acceleration of the particle as a function of $x$, is given by
A particle of unit mass undergoes one dimensional motion such that its velocity varies according to $ v(x)= \beta {x^{ - 2n}}$, where $\beta$ and $n$ are constants and $x$ is the position of the particle. The acceleration of the particle as a function of $x$, is given by
- [AIPMT 2015]