Gujarati
Hindi
6.Interest
hard

The difference between the compound interest and the simple interest accrued on an amount of ₹ $18000$ in $2$ years was ₹ $405 .$ What was the rate of interest per cent per annum?

A

$12$

B

$13$

C

$14$

D

$15$

Solution

Let rate of interest be $R \%$ p.a.

$S.I.  =\frac{18000 \times 2 \times R}{100}$

$C.I. =  18000\left[\left(1+\frac{R}{100}\right)^{2}-1\right]$

$(2)-(1) \Rightarrow 18000\left[\left(1+\frac{R}{100}\right)^{2}-1-\frac{2 R}{100}\right]$

$=405 or 18000\left[\left(\frac{R}{100}\right)^{2}\right]$$=405$

Or   $\left(\frac{R}{100}\right)^{2}=\frac{405}{18000}$

or   $=\frac{45}{2000}$$=\frac{9}{400}$$\frac{R}{100} =\frac{3}{20}$

Or   $R=15 \%$

Standard 13
Quantitative Aptitude

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