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6.Interest
hard
The difference between the compound interest and the simple interest accrued on an amount of ₹ $18000$ in $2$ years was ₹ $405 .$ What was the rate of interest per cent per annum?
A
$12$
B
$13$
C
$14$
D
$15$
Solution
Let rate of interest be $R \%$ p.a.
$S.I. =\frac{18000 \times 2 \times R}{100}$
$C.I. = 18000\left[\left(1+\frac{R}{100}\right)^{2}-1\right]$
$(2)-(1) \Rightarrow 18000\left[\left(1+\frac{R}{100}\right)^{2}-1-\frac{2 R}{100}\right]$
$=405 or 18000\left[\left(\frac{R}{100}\right)^{2}\right]$$=405$
Or $\left(\frac{R}{100}\right)^{2}=\frac{405}{18000}$
or $=\frac{45}{2000}$$=\frac{9}{400}$$\frac{R}{100} =\frac{3}{20}$
Or $R=15 \%$
Standard 13
Quantitative Aptitude
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