The dimensions of permittivity {varepsilon _0 | vedclass

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Question

(b) $F = \frac{1}{{4\pi {\varepsilon _0}}}\,\frac{{{q_1}{q_2}}}{{{r^2}}}$
$ \Rightarrow {\varepsilon _0} = \frac{{|{q_1}|\,|{q_2}|}}{{[F]\,[{r^2}]}}

Vedclass · Accepted Answer

${A^2}{T^4}{M^{ - 1}}{L^{ - 3}}$

Vedclass · Answer

(b) $F = \frac{1}{{4\pi {\varepsilon _0}}}\,\frac{{{q_1}{q_2}}}{{{r^2}}}$
$ \Rightarrow {\varepsilon _0} = \frac{{|{q_1}|\,|{q_2}|}}{{[F]\,[{r^2}]}} $ $= \frac{{[{A^2}{T^2}]}}{{[ML{T^{ - 2}}]\,[{L^2}]}} $ $= [{A^2}{T^4}{M^{ - 1}}{L^{ - 3}}]$

The dimensions of permittivity ${\varepsilon _0}$ are

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