The dipole moment of a short bar magnet is 1. | vedclass

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Question

(c)$B = \frac{{{\mu _0}}}{{4\pi }}\frac{{2M}}{{{d^3}}} = {10^{ - 7}} 	imes \frac{{2 	imes 1.25}}{{{{\left( {0.5} ight)}^3}}} = 2 	imes {10^{ - 6}

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$2 	imes {10^{ - 6}}\,Newton/amp - metre$

Vedclass · Answer

(c)$B = \frac{{{\mu _0}}}{{4\pi }}\frac{{2M}}{{{d^3}}} = {10^{ - 7}} 	imes \frac{{2 	imes 1.25}}{{{{\left( {0.5} ight)}^3}}} = 2 	imes {10^{ - 6}}\,N/A - m$

The dipole moment of a short bar magnet is $1.25\, A-m^2$. The magnetic field on its axis at a distance of $0.5$ metre from the centre of the magnet is

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