Displacement is given by x = 2{t^2} + t + 5 , acceleration at t = 2s is......... m/{s^2}

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2.Motion in Straight Line

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The displacement is given by $x = 2{t^2} + t + 5$, the acceleration at $t = 2\;s$ is.........$m/{s^2}$

A

$4$

B

$8$

C

$10$

D

$15$

Solution

(a) Displacement $x = 2{t^2} + t + 5$

Velocity $ = \frac{{dx}}{{dt}} = 4t + 1$

Acceleration $ = \frac{{{d^2}x}}{{d{t^2}}} = 4$ i.e. independent of time

Hence acceleration $ = 4\;m/{s^2}$

Standard 11

Physics

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