Displacement of a particle as a function of time is shown in figure. figure shows that

English

Gujarati

Hindi

2.Motion in Straight Line

easy

The displacement of a particle as a function of time is shown in the figure. The figure shows that

AThe particle starts with certain velocity but the motion is retarded and finally the particle stops

BThe velocity of the particle is constant throughout

CThe acceleration of the particle is constant throughout.

DThe particle starts with constant velocity, then motion is accelerated and finally the particle moves with another constant velocity

Solution

(a)The slope of displacement-time graph goes on decreasing, it means the velocity is decreasing i.e. It’s motion is retarded and finally slope becomes zero i.e. particle stops.

Standard 11

Physics

A particle moving along $x-$axis has acceleration $f$, at time $t$ , given by $ f=f_0$$\left( {1 – \frac{t}{T}} \right)$, where $f_0$ and $T$ are constants. The particle at $t=0$ has zero velocity . In the time interval between $t=0$ and the instant when $f=0$ , the particle 's velocity $(v_x)$ is

hard

(AIPMT-2007)

Which graph corresponds to an object moving with a constant negative acceleration and a positive velocity?

hard

(JEE MAIN-2017)

The relation between time and distance is $t = \alpha {x^2} + \beta x$, where $\alpha $ and $\beta $ are constants. The retardation is

hard

(AIEEE-2005)

The $v – t$ graph of a moving object is given in figure. The maximum acceleration is………..$\mathrm{cm/sec}^{2}$

medium

A particle starts moving rectilinearly at time $t = 0$ such that its velocity $'v'$ changes with time $'t'$ according to the equation $v = t^2 – t$ where $t$ is in seconds and $v$ is in $m/s.$ The time interval for which the particle retards is

hard

The displacement of a particle as a function of time is shown in the figure. The figure shows that

Solution

Similar Questions

Which graph corresponds to an object moving with a constant negative acceleration and a positive velocity?

The relation between time and distance is $t = \alpha {x^2} + \beta x$, where $\alpha $ and $\beta $ are constants. The retardation is

The $v – t$ graph of a moving object is given in figure. The maximum acceleration is………..$\mathrm{cm/sec}^{2}$

A particle starts moving rectilinearly at time $t = 0$ such that its velocity $'v'$ changes with time $'t'$ according to the equation $v = t^2 – t$ where $t$ is in seconds and $v$ is in $m/s.$ The time interval for which the particle retards is

Start a Free Trial Now