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2. Electric Potential and Capacitance
normal
The distance between plates of a parallel plate capacitor is $5d$. Let the positively charged plate is at $ x=0$ and negatively charged plate is at $x=5d$. Two slabs one of conductor and other of a dielectric of equal thickness $d$ are inserted between the plates as shown in figure. Potential versus distance graph will look like :

A

B

C

D

Solution
Voltage would be highest at $x=0 .$ And $E=$ constant $\Rightarrow \propto v \times$ so it would decrease linearly, from $x=0$ to $x$ $-d,$ will remain constant from $x=d$ to $x=2 d$
Standard 12
Physics