Distance-time graph of a particle at time t makes angle 45^{circ} with time axis. After one second,

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2.Motion in Straight Line

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The distance-time graph of a particle at time $t$ makes angle $45^{\circ}$ with the time axis. After one second, it makes angle $60^{\circ}$ with the time axis. What is the average acceleration of the particle?

A

$\sqrt{3}-1$

B

$\sqrt{3}+1$

C

$\sqrt{3}$

D

$1$

Solution

(a)

$v_i=\text { slope of } s-t \text { graph }=\tan 45^{\circ}=1\,m / s$

$v_f=\text { slope of } s-t \text { graph }=\tan 60^{\circ}=\sqrt{3}\,m / s$

Now $\quad a_{ av }=\frac{v_f-v_i}{\Delta t}=\frac{\sqrt{3}-1}{1}=(\sqrt{3}-1)$ units

Standard 11

Physics

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