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2.Motion in Straight Line
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The distance travelled by a body moving along a line in time $t$ is proportional to $t^3$. The acceleration-time $(a, t)$ graph for the motion of the body will be
A

B

C

D

(AIEEE-2012)
Solution
$\begin{array}{l}
{\rm{Distance}}\,along\,a\,{\rm{ilne}}\,{\rm{i}}{\rm{.e}}{\rm{.,}}\,{\rm{displacement}}\left( s \right)\\
= {t^3}\left( {\,s\, \propto \,{t^3}\,given} \right)\\
By\,double\,differentiation\,of\,displacement,\\
Wr\,get\,acceleration.\\
V = \frac{{ds}}{{dt}} = \frac{{d{t^3}}}{{dt}} = 3{t^2}\,and\\
a = \frac{{dv}}{{dt}} = \frac{{d3{t^2}}}{{dt}} = 6t\,\\
a = 6t\,or\,a \propto \,t\\
Hence\,graph\,(b)\,is\,correct.
\end{array}$
Standard 11
Physics
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