The distance travelled by a particle starting | vedclass

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Question

$\begin{array}{l}
{m{Distance}}\,travelled\,in\,the\,{3^{rd}}\,{m{second}}\
 = {m{Distance}}\,travelled\,in\,3\,s\
\,\,\,\,\,\,\,\,\,\

Vedclass · Accepted Answer

$\frac{{10}}{3}\,m$

Vedclass · Answer

$\begin{array}{l}
{m{Distance}}\,travelled\,in\,the\,{3^{rd}}\,{m{second}}\
 = {m{Distance}}\,travelled\,in\,3\,s\
\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, - \,d{m{istance}}\,{m{travelled}}\,{m{in}}\,\,{m{2}}\,\,{m{s}}{m{.}}\
As,\,u = 0,\
{S_{\left( {{3^{rd}}s} ight)}} = \frac{1}{2}a{.3^2} - \frac{1}{2}a \cdot {2^2} = \frac{1}{2}a \cdot 5\
Give\,a\frac{4}{5}m{s^{ - 2}};\,\,\,	herefore \,\,\,{S_{\left( {{3^{rd}}s} ight)}} = \frac{1}{2} 	imes \frac{4}{3} 	imes 5 = \frac{{10}}{3}\,m
\end{array}$

The distance travelled by a particle starting from rest and moving with an acceleration $\frac{4}{3}$ $ms^{-2}$ in the third second is

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