The eccentricity of ellipse $(x-3)^2 + (y -4)^2 = \frac{y^2}{9} +16 ,$ is -

  • A

    $\frac{{\sqrt 3 }}{2}$

  • B

    $\frac{1}{3}$

  • C

    $\frac{1}{{3\sqrt 2 }}$

  • D

    $\frac{1}{{\sqrt 3 }}$

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  • [JEE MAIN 2021]

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