Gujarati
10-2. Parabola, Ellipse, Hyperbola
easy

Eccentricity of the conic $16{x^2} + 7{y^2} = 112$ is

A

$3\over \sqrt 7 $

B

$7\over{16}$

C

$3\over4$

D

$4\over3$

Solution

(c) $\frac{{{x^2}}}{{\frac{{112}}{{16}}}} + \frac{{{y^2}}}{{\frac{{112}}{7}}} = 1$.

Therefore,  $e = \sqrt {1 – \frac{{112}}{{16}}.\frac{7}{{112}}} = \frac{3}{4}$.

Standard 11
Mathematics

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