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5.Magnetism and Matter
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The effective length of a magnet is $ 31.4 \,cm $ and its pole strength is $0.5\, Am$. The magnetic moment, if it is bent in the form of a semicircle will be.....$A{m^2}$
A
$0.1$
B
$0.01$
C
$0.2$
D
$1.2$
Solution
(a)New magnetic moment $M' = \frac{{2M}}{\pi } = \frac{{2mL}}{\pi } = \frac{{2 \times 0.5 \times 31.4 \times {{10}^{ – 2}}}}{{3.14}} = 0.1\,amp \times {m^2}$
Standard 12
Physics